2013140111201 has 4 divisors (see below), whose sum is σ = 2013143865600. Its totient is φ = 2013136356804.

The previous prime is 2013140111189. The next prime is 2013140111219. The reversal of 2013140111201 is 1021110413102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013140111201 - 2³⁸ = 1738262204257 is a prime.

It is a super-3 number, since 3×2013140111201³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2013140111201.

It is not an unprimeable number, because it can be changed into a prime (2013140111251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 905081 + ... + 2201238.

It is an arithmetic number, because the mean of its divisors is an integer number (503285966400).

Almost surely, 2^{2013140111201} is an apocalyptic number.

It is an amenable number.

2013140111201 is a deficient number, since it is larger than the sum of its proper divisors (3754399).

2013140111201 is an equidigital number, since it uses as much as digits as its factorization.

2013140111201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3754398.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 2013140111201 its reverse (1021110413102), we get a palindrome (3034250524303).

The spelling of 2013140111201 in words is "two trillion, thirteen billion, one hundred forty million, one hundred eleven thousand, two hundred one".