Base | Representation |
---|---|
bin | 11101010010111000100… |
… | …011111100001110100011 |
3 | 21010110021021012010011111 |
4 | 131102320203330032203 |
5 | 230440403111432003 |
6 | 4140454012524151 |
7 | 265305341133652 |
oct | 35227043741643 |
9 | 7113237163144 |
10 | 2013141124003 |
11 | 70684a755849 |
12 | 2861b0a80657 |
13 | 117ab8c47ba9 |
14 | 6d617c73199 |
15 | 37576a08e6d |
hex | 1d4b88fc3a3 |
2013141124003 has 2 divisors, whose sum is σ = 2013141124004. Its totient is φ = 2013141124002.
The previous prime is 2013141123953. The next prime is 2013141124039. The reversal of 2013141124003 is 3004211413102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013141124003 - 233 = 2004551189411 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013141124073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006570562001 + 1006570562002.
It is an arithmetic number, because the mean of its divisors is an integer number (1006570562002).
Almost surely, 22013141124003 is an apocalyptic number.
2013141124003 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013141124003 is an equidigital number, since it uses as much as digits as its factorization.
2013141124003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 2013141124003 its reverse (3004211413102), we get a palindrome (5017352537105).
The spelling of 2013141124003 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-four thousand, three".
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