Base | Representation |
---|---|
bin | 11101010010111000100… |
… | …011111100001111000111 |
3 | 21010110021021012010012211 |
4 | 131102320203330033013 |
5 | 230440403111432124 |
6 | 4140454012524251 |
7 | 265305341134033 |
oct | 35227043741707 |
9 | 7113237163184 |
10 | 2013141124039 |
11 | 70684a755881 |
12 | 2861b0a80687 |
13 | 117ab8c47c06 |
14 | 6d617c731c3 |
15 | 37576a08e94 |
hex | 1d4b88fc3c7 |
2013141124039 has 2 divisors, whose sum is σ = 2013141124040. Its totient is φ = 2013141124038.
The previous prime is 2013141124003. The next prime is 2013141124061. The reversal of 2013141124039 is 9304211413102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2013141124039 - 27 = 2013141123911 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2013141124039.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013141122039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006570562019 + 1006570562020.
It is an arithmetic number, because the mean of its divisors is an integer number (1006570562020).
Almost surely, 22013141124039 is an apocalyptic number.
2013141124039 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013141124039 is an equidigital number, since it uses as much as digits as its factorization.
2013141124039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 2013141124039 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-four thousand, thirty-nine".
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