Base | Representation |
---|---|
bin | 11101010010111000100… |
… | …011111100010100110011 |
3 | 21010110021021012010201022 |
4 | 131102320203330110303 |
5 | 230440403111440103 |
6 | 4140454012530055 |
7 | 265305341135063 |
oct | 35227043742463 |
9 | 7113237163638 |
10 | 2013141124403 |
11 | 70684a756082 |
12 | 2861b0a8092b |
13 | 117ab8c48126 |
14 | 6d617c733a3 |
15 | 37576a09138 |
hex | 1d4b88fc533 |
2013141124403 has 2 divisors, whose sum is σ = 2013141124404. Its totient is φ = 2013141124402.
The previous prime is 2013141124391. The next prime is 2013141124429. The reversal of 2013141124403 is 3044211413102.
It is an a-pointer prime, because the next prime (2013141124429) can be obtained adding 2013141124403 to its sum of digits (26).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013141124403 - 24 = 2013141124387 is a prime.
It is not a weakly prime, because it can be changed into another prime (2013141124493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006570562201 + 1006570562202.
It is an arithmetic number, because the mean of its divisors is an integer number (1006570562202).
Almost surely, 22013141124403 is an apocalyptic number.
2013141124403 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013141124403 is an equidigital number, since it uses as much as digits as its factorization.
2013141124403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 2013141124403 its reverse (3044211413102), we get a palindrome (5057352537505).
The spelling of 2013141124403 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-four thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.064 sec. • engine limits •