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2013141124403 is a prime number
BaseRepresentation
bin11101010010111000100…
…011111100010100110011
321010110021021012010201022
4131102320203330110303
5230440403111440103
64140454012530055
7265305341135063
oct35227043742463
97113237163638
102013141124403
1170684a756082
122861b0a8092b
13117ab8c48126
146d617c733a3
1537576a09138
hex1d4b88fc533

2013141124403 has 2 divisors, whose sum is σ = 2013141124404. Its totient is φ = 2013141124402.

The previous prime is 2013141124391. The next prime is 2013141124429. The reversal of 2013141124403 is 3044211413102.

It is an a-pointer prime, because the next prime (2013141124429) can be obtained adding 2013141124403 to its sum of digits (26).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2013141124403 - 24 = 2013141124387 is a prime.

It is not a weakly prime, because it can be changed into another prime (2013141124493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006570562201 + 1006570562202.

It is an arithmetic number, because the mean of its divisors is an integer number (1006570562202).

Almost surely, 22013141124403 is an apocalyptic number.

2013141124403 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013141124403 is an equidigital number, since it uses as much as digits as its factorization.

2013141124403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 2013141124403 its reverse (3044211413102), we get a palindrome (5057352537505).

The spelling of 2013141124403 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-four thousand, four hundred three".