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2013142133201 = 4914100085811
BaseRepresentation
bin11101010010111000100…
…111110010100111010001
321010110021100002101112012
4131102320213302213101
5230440403341230301
64140454050312305
7265305352536143
oct35227047624721
97113240071465
102013142133201
11706850284aa1
122861b1288695
13117ab920c354
146d618056c93
1537576b57ebb
hex1d4b89f29d1

2013142133201 has 4 divisors (see below), whose sum is σ = 2017242219504. Its totient is φ = 2009042046900.

The previous prime is 2013142133183. The next prime is 2013142133209. The reversal of 2013142133201 is 1023312413102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013142133201 - 26 = 2013142133137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013142133209) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2050042415 + ... + 2050043396.

It is an arithmetic number, because the mean of its divisors is an integer number (504310554876).

Almost surely, 22013142133201 is an apocalyptic number.

It is an amenable number.

2013142133201 is a deficient number, since it is larger than the sum of its proper divisors (4100086303).

2013142133201 is an equidigital number, since it uses as much as digits as its factorization.

2013142133201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4100086302.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 2013142133201 its reverse (1023312413102), we get a palindrome (3036454546303).

The spelling of 2013142133201 in words is "two trillion, thirteen billion, one hundred forty-two million, one hundred thirty-three thousand, two hundred one".

Divisors: 1 491 4100085811 2013142133201