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2013143201313 = 3671047733771
BaseRepresentation
bin11101010010111000101…
…011110111011000100001
321010110021102002122200220
4131102320223313120201
5230440404124420223
64140454125233253
7265305364605156
oct35227053673041
97113242078626
102013143201313
11706850944532
122861b1702829
13117ab94c457a
146d61825422d
1537576cb96e3
hex1d4b8af7621

2013143201313 has 4 divisors (see below), whose sum is σ = 2684190935088. Its totient is φ = 1342095467540.

The previous prime is 2013143201299. The next prime is 2013143201317. The reversal of 2013143201313 is 3131023413102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2013143201313 - 28 = 2013143201057 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2013143201317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335523866883 + ... + 335523866888.

It is an arithmetic number, because the mean of its divisors is an integer number (671047733772).

Almost surely, 22013143201313 is an apocalyptic number.

It is an amenable number.

2013143201313 is a deficient number, since it is larger than the sum of its proper divisors (671047733775).

2013143201313 is an equidigital number, since it uses as much as digits as its factorization.

2013143201313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671047733774.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 2013143201313 its reverse (3131023413102), we get a palindrome (5144166614415).

The spelling of 2013143201313 in words is "two trillion, thirteen billion, one hundred forty-three million, two hundred one thousand, three hundred thirteen".

Divisors: 1 3 671047733771 2013143201313