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201314537 is a prime number
BaseRepresentation
bin10111111111111…
…01000011101001
3112000210211121222
423333331003221
5403014031122
631550511425
74663100564
oct1377750351
9460724558
10201314537
11a3700656
1257505575
1332927738
141ca454db
1512a18b42
hexbffd0e9

201314537 has 2 divisors, whose sum is σ = 201314538. Its totient is φ = 201314536.

The previous prime is 201314507. The next prime is 201314539. The reversal of 201314537 is 735413102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121462441 + 79852096 = 11021^2 + 8936^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201314537 is a prime.

It is a super-3 number, since 3×2013145373 (a number of 26 digits) contains 333 as substring.

Together with 201314539, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (201314539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100657268 + 100657269.

It is an arithmetic number, because the mean of its divisors is an integer number (100657269).

Almost surely, 2201314537 is an apocalyptic number.

It is an amenable number.

201314537 is a deficient number, since it is larger than the sum of its proper divisors (1).

201314537 is an equidigital number, since it uses as much as digits as its factorization.

201314537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 201314537 is about 14188.5354071518. The cubic root of 201314537 is about 586.0819939471.

Adding to 201314537 its reverse (735413102), we get a palindrome (936727639).

The spelling of 201314537 in words is "two hundred one million, three hundred fourteen thousand, five hundred thirty-seven".