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201316282413 = 367105427471
BaseRepresentation
bin1011101101111101100…
…0101011000000101101
3201020122002002202111220
42323133120223000231
511244243432014123
6232252230333553
720354543111031
oct2733730530055
9636562082456
10201316282413
117841787a704
12330244ba2b9
1315ca3c383cc
149a5ac401c1
155383ccdce3
hex2edf62b02d

201316282413 has 4 divisors (see below), whose sum is σ = 268421709888. Its totient is φ = 134210854940.

The previous prime is 201316282399. The next prime is 201316282463. The reversal of 201316282413 is 314282613102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201316282413 - 229 = 200779411501 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201316282463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33552713733 + ... + 33552713738.

It is an arithmetic number, because the mean of its divisors is an integer number (67105427472).

Almost surely, 2201316282413 is an apocalyptic number.

It is an amenable number.

201316282413 is a deficient number, since it is larger than the sum of its proper divisors (67105427475).

201316282413 is an equidigital number, since it uses as much as digits as its factorization.

201316282413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67105427474.

The product of its (nonzero) digits is 13824, while the sum is 33.

Adding to 201316282413 its reverse (314282613102), we get a palindrome (515598895515).

The spelling of 201316282413 in words is "two hundred one billion, three hundred sixteen million, two hundred eighty-two thousand, four hundred thirteen".

Divisors: 1 3 67105427471 201316282413