Base | Representation |
---|---|
bin | 10010101111111101… |
… | …011111010011110011 |
3 | 1220222000220121121002 |
4 | 102233331133103303 |
5 | 312212243013021 |
6 | 13125402352215 |
7 | 1311614120333 |
oct | 225775372363 |
9 | 56860817532 |
10 | 20132001011 |
11 | 85a0a98371 |
12 | 3a9a1bb66b |
13 | 1b8ab44145 |
14 | d8da470c3 |
15 | 7cc64250b |
hex | 4aff5f4f3 |
20132001011 has 4 divisors (see below), whose sum is σ = 20290520832. Its totient is φ = 19973481192.
The previous prime is 20132000971. The next prime is 20132001023. The reversal of 20132001011 is 11010023102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20132001011 - 222 = 20127806707 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 20132000983 and 20132001001.
It is not an unprimeable number, because it can be changed into a prime (20132001031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79259720 + ... + 79259973.
It is an arithmetic number, because the mean of its divisors is an integer number (5072630208).
Almost surely, 220132001011 is an apocalyptic number.
20132001011 is a deficient number, since it is larger than the sum of its proper divisors (158519821).
20132001011 is a wasteful number, since it uses less digits than its factorization.
20132001011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158519820.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 20132001011 its reverse (11010023102), we get a palindrome (31142024113).
The spelling of 20132001011 in words is "twenty billion, one hundred thirty-two million, one thousand, eleven".
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