Base | Representation |
---|---|
bin | 10010101111111101… |
… | …011111010101100001 |
3 | 1220222000220121202011 |
4 | 102233331133111201 |
5 | 312212243013441 |
6 | 13125402352521 |
7 | 1311614120551 |
oct | 225775372541 |
9 | 56860817664 |
10 | 20132001121 |
11 | 85a0a98461 |
12 | 3a9a1bb741 |
13 | 1b8ab441cb |
14 | d8da47161 |
15 | 7cc642581 |
hex | 4aff5f561 |
20132001121 has 4 divisors (see below), whose sum is σ = 20781420544. Its totient is φ = 19482581700.
The previous prime is 20132001119. The next prime is 20132001151. The reversal of 20132001121 is 12110023102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20132001121 - 21 = 20132001119 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20132001151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324709665 + ... + 324709726.
It is an arithmetic number, because the mean of its divisors is an integer number (5195355136).
Almost surely, 220132001121 is an apocalyptic number.
It is an amenable number.
20132001121 is a deficient number, since it is larger than the sum of its proper divisors (649419423).
20132001121 is an equidigital number, since it uses as much as digits as its factorization.
20132001121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 649419422.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20132001121 its reverse (12110023102), we get a palindrome (32242024223).
The spelling of 20132001121 in words is "twenty billion, one hundred thirty-two million, one thousand, one hundred twenty-one".
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