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20132001300403 = 40949222497067
BaseRepresentation
bin1001001001111010110001…
…10010010011111110110011
32122021121012210012100022201
410210331120302103332303
510114320314313103103
6110452302544044031
74145326521405166
oct444753062237663
978247183170281
1020132001300403
116461a2a991843
122311872603617
13b30593999795
144d857343dadd
1524da2d76751d
hex124f58c93fb3

20132001300403 has 4 divisors (see below), whose sum is σ = 20181223797880. Its totient is φ = 20082778802928.

The previous prime is 20132001300347. The next prime is 20132001300427. The reversal of 20132001300403 is 30400310023102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20132001300403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20132001300493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24611248125 + ... + 24611248942.

It is an arithmetic number, because the mean of its divisors is an integer number (5045305949470).

Almost surely, 220132001300403 is an apocalyptic number.

20132001300403 is a deficient number, since it is larger than the sum of its proper divisors (49222497477).

20132001300403 is an equidigital number, since it uses as much as digits as its factorization.

20132001300403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49222497476.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 20132001300403 its reverse (30400310023102), we get a palindrome (50532311323505).

The spelling of 20132001300403 in words is "twenty trillion, one hundred thirty-two billion, one million, three hundred thousand, four hundred three".

Divisors: 1 409 49222497067 20132001300403