Base | Representation |
---|---|
bin | 1001001001111010110010… |
… | …10100110000101110011111 |
3 | 2122021121020102012011000201 |
4 | 10210331121110300232133 |
5 | 10114320324121043124 |
6 | 110452303505404331 |
7 | 4145326661226445 |
oct | 444753124605637 |
9 | 78247212164021 |
10 | 20132010331039 |
11 | 6461a34a9a682 |
12 | 23118756396a7 |
13 | b3059580c059 |
14 | 4d8574710b95 |
15 | 24da2e44d144 |
hex | 124f59530b9f |
20132010331039 has 2 divisors, whose sum is σ = 20132010331040. Its totient is φ = 20132010331038.
The previous prime is 20132010330953. The next prime is 20132010331049. The reversal of 20132010331039 is 93013301023102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20132010331039 - 213 = 20132010322847 is a prime.
It is a super-2 number, since 2×201320103310392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20132010330998 and 20132010331016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132010331049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066005165519 + 10066005165520.
It is an arithmetic number, because the mean of its divisors is an integer number (10066005165520).
Almost surely, 220132010331039 is an apocalyptic number.
20132010331039 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132010331039 is an equidigital number, since it uses as much as digits as its factorization.
20132010331039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 28.
The spelling of 20132010331039 in words is "twenty trillion, one hundred thirty-two billion, ten million, three hundred thirty-one thousand, thirty-nine".
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