Base | Representation |
---|---|
bin | 1001001001111010110010… |
… | …11011001011001100010111 |
3 | 2122021121020112100120022001 |
4 | 10210331121123023030113 |
5 | 10114320330033343221 |
6 | 110452304005420131 |
7 | 4145330011431223 |
oct | 444753133131427 |
9 | 78247215316261 |
10 | 20132012012311 |
11 | 6461a35a38861 |
12 | 231187610a647 |
13 | b30595c7a3a4 |
14 | 4d8574a2b783 |
15 | 24da2e681391 |
hex | 124f596cb317 |
20132012012311 has 4 divisors (see below), whose sum is σ = 20560352693472. Its totient is φ = 19703671331152.
The previous prime is 20132012012207. The next prime is 20132012012353. The reversal of 20132012012311 is 11321021023102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20132012012311 - 229 = 20131475141399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20132012012911) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214170340510 + ... + 214170340603.
It is an arithmetic number, because the mean of its divisors is an integer number (5140088173368).
Almost surely, 220132012012311 is an apocalyptic number.
20132012012311 is a deficient number, since it is larger than the sum of its proper divisors (428340681161).
20132012012311 is an equidigital number, since it uses as much as digits as its factorization.
20132012012311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 428340681160.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 20132012012311 its reverse (11321021023102), we get a palindrome (31453033035413).
The spelling of 20132012012311 in words is "twenty trillion, one hundred thirty-two billion, twelve million, twelve thousand, three hundred eleven".
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