2013201211231 has 4 divisors (see below), whose sum is σ = 2300801384272. Its totient is φ = 1725601038192.

The previous prime is 2013201211183. The next prime is 2013201211261. The reversal of 2013201211231 is 1321121023102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013201211231 - 2⁹ = 2013201210719 is a prime.

It is a super-2 number, since 2×2013201211231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013201211199 and 2013201211208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013201211261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 143800086510 + ... + 143800086523.

It is an arithmetic number, because the mean of its divisors is an integer number (575200346068).

Almost surely, 2^{2013201211231} is an apocalyptic number.

2013201211231 is a deficient number, since it is larger than the sum of its proper divisors (287600173041).

2013201211231 is an equidigital number, since it uses as much as digits as its factorization.

2013201211231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 287600173040.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2013201211231 its reverse (1321121023102), we get a palindrome (3334322234333).

The spelling of 2013201211231 in words is "two trillion, thirteen billion, two hundred one million, two hundred eleven thousand, two hundred thirty-one".