Base | Representation |
---|---|
bin | 11101010010111100001… |
… | …100101010100000111001 |
3 | 21010110102111222121000221 |
4 | 131102330030222200321 |
5 | 230441014221143001 |
6 | 4140504032300041 |
7 | 265310011523635 |
oct | 35227414524071 |
9 | 7113374877027 |
10 | 2013202131001 |
11 | 706881134256 |
12 | 2862093a1621 |
13 | 117ac87882c9 |
14 | 6d621dd3dc5 |
15 | 3757c05a1a1 |
hex | 1d4bc32a839 |
2013202131001 has 4 divisors (see below), whose sum is σ = 2013709622272. Its totient is φ = 2012694639732.
The previous prime is 2013202130983. The next prime is 2013202131023. The reversal of 2013202131001 is 1001312023102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2013202131001 - 25 = 2013202130969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2013202131071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253739685 + ... + 253747618.
It is an arithmetic number, because the mean of its divisors is an integer number (503427405568).
Almost surely, 22013202131001 is an apocalyptic number.
It is an amenable number.
2013202131001 is a deficient number, since it is larger than the sum of its proper divisors (507491271).
2013202131001 is an equidigital number, since it uses as much as digits as its factorization.
2013202131001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 507491270.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 2013202131001 its reverse (1001312023102), we get a palindrome (3014514154103).
The spelling of 2013202131001 in words is "two trillion, thirteen billion, two hundred two million, one hundred thirty-one thousand, one".
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