Base | Representation |
---|---|
bin | 11101010010111100001… |
… | …101000101001011001011 |
3 | 21010110102112012010211110 |
4 | 131102330031011023023 |
5 | 230441014233141303 |
6 | 4140504034501403 |
7 | 265310012460210 |
oct | 35227415051313 |
9 | 7113375163743 |
10 | 2013202240203 |
11 | 7068811a9300 |
12 | 286209434863 |
13 | 117ac87c5c1b |
14 | 6d622021b07 |
15 | 3757c07c703 |
hex | 1d4bc3452cb |
2013202240203 has 48 divisors (see below), whose sum is σ = 3378031292160. Its totient is φ = 1043941018560.
The previous prime is 2013202240201. The next prime is 2013202240211. The reversal of 2013202240203 is 3020422023102.
It is not a de Polignac number, because 2013202240203 - 21 = 2013202240201 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 2013202240203.
It is not an unprimeable number, because it can be changed into a prime (2013202240201) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 704128 + ... + 2126546.
It is an arithmetic number, because the mean of its divisors is an integer number (70375651920).
Almost surely, 22013202240203 is an apocalyptic number.
2013202240203 is a deficient number, since it is larger than the sum of its proper divisors (1364829051957).
2013202240203 is a wasteful number, since it uses less digits than its factorization.
2013202240203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1423008 (or 1422997 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 2013202240203 its reverse (3020422023102), we get a palindrome (5033624263305).
The spelling of 2013202240203 in words is "two trillion, thirteen billion, two hundred two million, two hundred forty thousand, two hundred three".
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