Base | Representation |
---|---|
bin | 1001001001111010110110… |
… | …01111000110011111011011 |
3 | 2122021121022122112111210000 |
4 | 10210331123033012133123 |
5 | 10114320410323324010 |
6 | 110452311013024043 |
7 | 4145330530641204 |
oct | 444753317063733 |
9 | 78247278474700 |
10 | 20132042401755 |
11 | 6461a511048a9 |
12 | 2311884325023 |
13 | b3059c35a6cb |
14 | 4d8578a9c5ab |
15 | 24da321857c0 |
hex | 124f5b3c67db |
20132042401755 has 40 divisors (see below), whose sum is σ = 36144328838112. Its totient is φ = 10720493949312.
The previous prime is 20132042401739. The next prime is 20132042401771. The reversal of 20132042401755 is 55710424023102.
20132042401755 is a `hidden beast` number, since 20 + 1 + 320 + 4 + 240 + 1 + 75 + 5 = 666.
It is an interprime number because it is at equal distance from previous prime (20132042401739) and next prime (20132042401771).
It is not a de Polignac number, because 20132042401755 - 24 = 20132042401739 is a prime.
It is a super-2 number, since 2×201320424017552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 38152762 + ... + 38676831.
Almost surely, 220132042401755 is an apocalyptic number.
20132042401755 is a deficient number, since it is larger than the sum of its proper divisors (16012286436357).
20132042401755 is an equidigital number, since it uses as much as digits as its factorization.
20132042401755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76830257 (or 76830248 counting only the distinct ones).
The product of its (nonzero) digits is 67200, while the sum is 36.
Adding to 20132042401755 its reverse (55710424023102), we get a palindrome (75842466424857).
The spelling of 20132042401755 in words is "twenty trillion, one hundred thirty-two billion, forty-two million, four hundred one thousand, seven hundred fifty-five".
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