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20132100041 is a prime number
BaseRepresentation
bin10010101111111101…
…110111011111001001
31220222001002122102212
4102233331313133021
5312212304200131
613125404434505
71311615012134
oct225775673711
956861078385
1020132100041
1185a1055809
123a9a248a35
131b8ab7a241
14d8da7121b
157cc661a2b
hex4aff777c9

20132100041 has 2 divisors, whose sum is σ = 20132100042. Its totient is φ = 20132100040.

The previous prime is 20132100017. The next prime is 20132100049. The reversal of 20132100041 is 14000123102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19706544400 + 425555641 = 140380^2 + 20629^2 .

It is a cyclic number.

It is not a de Polignac number, because 20132100041 - 222 = 20127905737 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 20132099989 and 20132100025.

It is not a weakly prime, because it can be changed into another prime (20132100049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066050020 + 10066050021.

It is an arithmetic number, because the mean of its divisors is an integer number (10066050021).

Almost surely, 220132100041 is an apocalyptic number.

It is an amenable number.

20132100041 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132100041 is an equidigital number, since it uses as much as digits as its factorization.

20132100041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 20132100041 its reverse (14000123102), we get a palindrome (34132223143).

The spelling of 20132100041 in words is "twenty billion, one hundred thirty-two million, one hundred thousand, forty-one".