Base | Representation |
---|---|
bin | 10010101111111101… |
… | …110111011111001001 |
3 | 1220222001002122102212 |
4 | 102233331313133021 |
5 | 312212304200131 |
6 | 13125404434505 |
7 | 1311615012134 |
oct | 225775673711 |
9 | 56861078385 |
10 | 20132100041 |
11 | 85a1055809 |
12 | 3a9a248a35 |
13 | 1b8ab7a241 |
14 | d8da7121b |
15 | 7cc661a2b |
hex | 4aff777c9 |
20132100041 has 2 divisors, whose sum is σ = 20132100042. Its totient is φ = 20132100040.
The previous prime is 20132100017. The next prime is 20132100049. The reversal of 20132100041 is 14000123102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19706544400 + 425555641 = 140380^2 + 20629^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132100041 - 222 = 20127905737 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 20132099989 and 20132100025.
It is not a weakly prime, because it can be changed into another prime (20132100049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066050020 + 10066050021.
It is an arithmetic number, because the mean of its divisors is an integer number (10066050021).
Almost surely, 220132100041 is an apocalyptic number.
It is an amenable number.
20132100041 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132100041 is an equidigital number, since it uses as much as digits as its factorization.
20132100041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 20132100041 its reverse (14000123102), we get a palindrome (34132223143).
The spelling of 20132100041 in words is "twenty billion, one hundred thirty-two million, one hundred thousand, forty-one".
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