Base | Representation |
---|---|
bin | 10010101111111101… |
… | …110111011110110001 |
3 | 1220222001002122101222 |
4 | 102233331313132301 |
5 | 312212304200032 |
6 | 13125404434425 |
7 | 1311615012101 |
oct | 225775673661 |
9 | 56861078358 |
10 | 20132100017 |
11 | 85a1055797 |
12 | 3a9a248a15 |
13 | 1b8ab7a223 |
14 | d8da71201 |
15 | 7cc661a12 |
hex | 4aff777b1 |
20132100017 has 2 divisors, whose sum is σ = 20132100018. Its totient is φ = 20132100016.
The previous prime is 20132100013. The next prime is 20132100041. The reversal of 20132100017 is 71000123102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18962391616 + 1169708401 = 137704^2 + 34201^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132100017 - 22 = 20132100013 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20132099968 and 20132100004.
It is not a weakly prime, because it can be changed into another prime (20132100013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066050008 + 10066050009.
It is an arithmetic number, because the mean of its divisors is an integer number (10066050009).
Almost surely, 220132100017 is an apocalyptic number.
It is an amenable number.
20132100017 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132100017 is an equidigital number, since it uses as much as digits as its factorization.
20132100017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 20132100017 its reverse (71000123102), we get a palindrome (91132223119).
The spelling of 20132100017 in words is "twenty billion, one hundred thirty-two million, one hundred thousand, seventeen".
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