Base | Representation |
---|---|
bin | 10010101111111101… |
… | …110111100010001001 |
3 | 1220222001002122200222 |
4 | 102233331313202021 |
5 | 312212304201413 |
6 | 13125404435425 |
7 | 1311615012530 |
oct | 225775674211 |
9 | 56861078628 |
10 | 20132100233 |
11 | 85a1055973 |
12 | 3a9a248b75 |
13 | 1b8ab7a35b |
14 | d8da71317 |
15 | 7cc661b08 |
hex | 4aff77889 |
20132100233 has 4 divisors (see below), whose sum is σ = 23008114560. Its totient is φ = 17256085908.
The previous prime is 20132100221. The next prime is 20132100293. The reversal of 20132100233 is 33200123102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33200123102 = 2 ⋅16600061551.
It is a cyclic number.
It is not a de Polignac number, because 20132100233 - 224 = 20115323017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20132100293) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438007153 + ... + 1438007166.
It is an arithmetic number, because the mean of its divisors is an integer number (5752028640).
Almost surely, 220132100233 is an apocalyptic number.
It is an amenable number.
20132100233 is a deficient number, since it is larger than the sum of its proper divisors (2876014327).
20132100233 is an equidigital number, since it uses as much as digits as its factorization.
20132100233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2876014326.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 20132100233 its reverse (33200123102), we get a palindrome (53332223335).
The spelling of 20132100233 in words is "twenty billion, one hundred thirty-two million, one hundred thousand, two hundred thirty-three".
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