Base | Representation |
---|---|
bin | 1011101101111110101… |
… | …1000011011011110001 |
3 | 201020122102011120102121 |
4 | 2323133223003123301 |
5 | 11244301200213131 |
6 | 232252521514241 |
7 | 20354632060354 |
oct | 2733753033361 |
9 | 636572146377 |
10 | 201321101041 |
11 | 7841a570a45 |
12 | 33026042981 |
13 | 15ca4c34778 |
14 | 9a5b73629b |
15 | 5384431911 |
hex | 2edfac36f1 |
201321101041 has 2 divisors, whose sum is σ = 201321101042. Its totient is φ = 201321101040.
The previous prime is 201321101039. The next prime is 201321101063. The reversal of 201321101041 is 140101123102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 178134643600 + 23186457441 = 422060^2 + 152271^2 .
It is a cyclic number.
It is not a de Polignac number, because 201321101041 - 21 = 201321101039 is a prime.
Together with 201321101039, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (201321141041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100660550520 + 100660550521.
It is an arithmetic number, because the mean of its divisors is an integer number (100660550521).
Almost surely, 2201321101041 is an apocalyptic number.
It is an amenable number.
201321101041 is a deficient number, since it is larger than the sum of its proper divisors (1).
201321101041 is an equidigital number, since it uses as much as digits as its factorization.
201321101041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 201321101041 its reverse (140101123102), we get a palindrome (341422224143).
The spelling of 201321101041 in words is "two hundred one billion, three hundred twenty-one million, one hundred one thousand, forty-one".
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