Base | Representation |
---|---|
bin | 1001001001111010111110… |
… | …11001101111011111110111 |
3 | 2122021121111112001201011202 |
4 | 10210331133121233133313 |
5 | 10114321031222100043 |
6 | 110452321551123115 |
7 | 4145332340032223 |
oct | 444753731573767 |
9 | 78247445051152 |
10 | 20132112300023 |
11 | 6461a87606469 |
12 | 23118a381349b |
13 | b305b0991b29 |
14 | 4d8584095783 |
15 | 24da383911b8 |
hex | 124f5f66f7f7 |
20132112300023 has 2 divisors, whose sum is σ = 20132112300024. Its totient is φ = 20132112300022.
The previous prime is 20132112300019. The next prime is 20132112300031. The reversal of 20132112300023 is 32000321123102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20132112300023 - 22 = 20132112300019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20132112299968 and 20132112300004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132112300073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066056150011 + 10066056150012.
It is an arithmetic number, because the mean of its divisors is an integer number (10066056150012).
Almost surely, 220132112300023 is an apocalyptic number.
20132112300023 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132112300023 is an equidigital number, since it uses as much as digits as its factorization.
20132112300023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 20132112300023 its reverse (32000321123102), we get a palindrome (52132433423125).
The spelling of 20132112300023 in words is "twenty trillion, one hundred thirty-two billion, one hundred twelve million, three hundred thousand, twenty-three".
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