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20132112300023 is a prime number
BaseRepresentation
bin1001001001111010111110…
…11001101111011111110111
32122021121111112001201011202
410210331133121233133313
510114321031222100043
6110452321551123115
74145332340032223
oct444753731573767
978247445051152
1020132112300023
116461a87606469
1223118a381349b
13b305b0991b29
144d8584095783
1524da383911b8
hex124f5f66f7f7

20132112300023 has 2 divisors, whose sum is σ = 20132112300024. Its totient is φ = 20132112300022.

The previous prime is 20132112300019. The next prime is 20132112300031. The reversal of 20132112300023 is 32000321123102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 20132112300023 - 22 = 20132112300019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20132112299968 and 20132112300004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20132112300073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066056150011 + 10066056150012.

It is an arithmetic number, because the mean of its divisors is an integer number (10066056150012).

Almost surely, 220132112300023 is an apocalyptic number.

20132112300023 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132112300023 is an equidigital number, since it uses as much as digits as its factorization.

20132112300023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 20132112300023 its reverse (32000321123102), we get a palindrome (52132433423125).

The spelling of 20132112300023 in words is "twenty trillion, one hundred thirty-two billion, one hundred twelve million, three hundred thousand, twenty-three".