Base | Representation |
---|---|
bin | 11101010010111100110… |
… | …111010100010001100111 |
3 | 21010110110022000122121211 |
4 | 131102330313110101213 |
5 | 230441030101441403 |
6 | 4140505112052251 |
7 | 265310205542620 |
oct | 35227467242147 |
9 | 7113408018554 |
10 | 2013213312103 |
11 | 706887480834 |
12 | 286211094087 |
13 | 117acaba1646 |
14 | 6d6236a4a47 |
15 | 3757d01806d |
hex | 1d4bcdd4467 |
2013213312103 has 16 divisors (see below), whose sum is σ = 2322961551360. Its totient is φ = 1709080567200.
The previous prime is 2013213312091. The next prime is 2013213312107. The reversal of 2013213312103 is 3012133123102.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2013213312103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2013213312107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2981533 + ... + 3593878.
It is an arithmetic number, because the mean of its divisors is an integer number (145185096960).
Almost surely, 22013213312103 is an apocalyptic number.
2013213312103 is a deficient number, since it is larger than the sum of its proper divisors (309748239257).
2013213312103 is a wasteful number, since it uses less digits than its factorization.
2013213312103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6575838.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 2013213312103 its reverse (3012133123102), we get a palindrome (5025346435205).
The spelling of 2013213312103 in words is "two trillion, thirteen billion, two hundred thirteen million, three hundred twelve thousand, one hundred three".
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