Base | Representation |
---|---|
bin | 10010101111111110… |
… | …000000000011111001 |
3 | 1220222001011102121121 |
4 | 102233332000003321 |
5 | 312212311311121 |
6 | 13125405305241 |
7 | 1311615216415 |
oct | 225776000371 |
9 | 56861142547 |
10 | 20132135161 |
11 | 85a107a136 |
12 | 3a9a265221 |
13 | 1b8ab90218 |
14 | d8da7dd45 |
15 | 7cc66c141 |
hex | 4aff800f9 |
20132135161 has 2 divisors, whose sum is σ = 20132135162. Its totient is φ = 20132135160.
The previous prime is 20132135113. The next prime is 20132135203. The reversal of 20132135161 is 16153123102.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10733996025 + 9398139136 = 103605^2 + 96944^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132135161 - 211 = 20132133113 is a prime.
It is a super-2 number, since 2×201321351612 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20132135761) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066067580 + 10066067581.
It is an arithmetic number, because the mean of its divisors is an integer number (10066067581).
Almost surely, 220132135161 is an apocalyptic number.
It is an amenable number.
20132135161 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132135161 is an equidigital number, since it uses as much as digits as its factorization.
20132135161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 20132135161 its reverse (16153123102), we get a palindrome (36285258263).
The spelling of 20132135161 in words is "twenty billion, one hundred thirty-two million, one hundred thirty-five thousand, one hundred sixty-one".
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