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201322113141431 is a prime number
BaseRepresentation
bin101101110001100111110101…
…000010100000101010110111
3222101211012120012202111010202
4231301213311002200222313
5202341430141431011211
61552102034010311115
760256020432512252
oct5561476502405267
9871735505674122
10201322113141431
1159169257458a37
121a6b56a842849b
1388447947a0499
1437a0083da2099
151841cb44e153b
hexb719f50a0ab7

201322113141431 has 2 divisors, whose sum is σ = 201322113141432. Its totient is φ = 201322113141430.

The previous prime is 201322113141367. The next prime is 201322113141437. The reversal of 201322113141431 is 134141311223102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 201322113141431 - 26 = 201322113141367 is a prime.

It is a super-2 number, since 2×2013221131414312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201322113141394 and 201322113141403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201322113141437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661056570715 + 100661056570716.

It is an arithmetic number, because the mean of its divisors is an integer number (100661056570716).

Almost surely, 2201322113141431 is an apocalyptic number.

201322113141431 is a deficient number, since it is larger than the sum of its proper divisors (1).

201322113141431 is an equidigital number, since it uses as much as digits as its factorization.

201322113141431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 201322113141431 its reverse (134141311223102), we get a palindrome (335463424364533).

The spelling of 201322113141431 in words is "two hundred one trillion, three hundred twenty-two billion, one hundred thirteen million, one hundred forty-one thousand, four hundred thirty-one".