Base | Representation |
---|---|
bin | 1001001001111011001011… |
… | …10100010000101110001101 |
3 | 2122021121210000120010101011 |
4 | 10210331211310100232031 |
5 | 10114321241244241044 |
6 | 110452340353445221 |
7 | 4145335114532026 |
oct | 444754564205615 |
9 | 78247700503334 |
10 | 20132219915149 |
11 | 6462032329291 |
12 | 2311913870811 |
13 | b305ca070814 |
14 | 4d85944a9c4d |
15 | 24da42a4c134 |
hex | 124f65d10b8d |
20132219915149 has 2 divisors, whose sum is σ = 20132219915150. Its totient is φ = 20132219915148.
The previous prime is 20132219915081. The next prime is 20132219915161. The reversal of 20132219915149 is 94151991223102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13877994201124 + 6254225714025 = 3725318^2 + 2500845^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132219915149 - 211 = 20132219913101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20132219915179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066109957574 + 10066109957575.
It is an arithmetic number, because the mean of its divisors is an integer number (10066109957575).
Almost surely, 220132219915149 is an apocalyptic number.
It is an amenable number.
20132219915149 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132219915149 is an equidigital number, since it uses as much as digits as its factorization.
20132219915149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 349920, while the sum is 49.
The spelling of 20132219915149 in words is "twenty trillion, one hundred thirty-two billion, two hundred nineteen million, nine hundred fifteen thousand, one hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •