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20132241411341 is a prime number
BaseRepresentation
bin1001001001111011001110…
…00110010000110100001101
32122021121211112000020121102
410210331213012100310031
510114321312300130331
6110452342442312445
74145335465332113
oct444754706206415
978247745006542
1020132241411341
116462043480734
12231191aab8725
13b30601658c67
144d85972a3ab3
1524da448964cb
hex124f67190d0d

20132241411341 has 2 divisors, whose sum is σ = 20132241411342. Its totient is φ = 20132241411340.

The previous prime is 20132241411319. The next prime is 20132241411383. The reversal of 20132241411341 is 14311414223102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19862807746441 + 269433664900 = 4456771^2 + 519070^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20132241411341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20132241401341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066120705670 + 10066120705671.

It is an arithmetic number, because the mean of its divisors is an integer number (10066120705671).

Almost surely, 220132241411341 is an apocalyptic number.

It is an amenable number.

20132241411341 is a deficient number, since it is larger than the sum of its proper divisors (1).

20132241411341 is an equidigital number, since it uses as much as digits as its factorization.

20132241411341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 20132241411341 its reverse (14311414223102), we get a palindrome (34443655634443).

The spelling of 20132241411341 in words is "twenty trillion, one hundred thirty-two billion, two hundred forty-one million, four hundred eleven thousand, three hundred forty-one".