Base | Representation |
---|---|
bin | 10010101111111110… |
… | …101000111001100001 |
3 | 1220222001110221001212 |
4 | 102233332220321201 |
5 | 312212332134213 |
6 | 13125413035505 |
7 | 1311616514165 |
oct | 225776507141 |
9 | 56861427055 |
10 | 20132302433 |
11 | 85a1183881 |
12 | 3a9a325b95 |
13 | 1b8ac1b3b9 |
14 | d8dac4ca5 |
15 | 7cc6a19a8 |
hex | 4affa8e61 |
20132302433 has 2 divisors, whose sum is σ = 20132302434. Its totient is φ = 20132302432.
The previous prime is 20132302429. The next prime is 20132302453. The reversal of 20132302433 is 33420323102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12408177664 + 7724124769 = 111392^2 + 87887^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132302433 - 22 = 20132302429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20132302399 and 20132302408.
It is not a weakly prime, because it can be changed into another prime (20132302453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066151216 + 10066151217.
It is an arithmetic number, because the mean of its divisors is an integer number (10066151217).
Almost surely, 220132302433 is an apocalyptic number.
It is an amenable number.
20132302433 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132302433 is an equidigital number, since it uses as much as digits as its factorization.
20132302433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 20132302433 its reverse (33420323102), we get a palindrome (53552625535).
The spelling of 20132302433 in words is "twenty billion, one hundred thirty-two million, three hundred two thousand, four hundred thirty-three".
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