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2013233404403 = 13154864108031
BaseRepresentation
bin11101010010111110000…
…011111101100111110011
321010110111200211110002002
4131102332003331213303
5230441100222420103
64140511110444215
7265310541405014
oct35227603754763
97113450743062
102013233404403
11706897854441
1228621796366b
13117b020b7a90
146d62621500b
153757eb86488
hex1d4be0fd9f3

2013233404403 has 4 divisors (see below), whose sum is σ = 2168097512448. Its totient is φ = 1858369296360.

The previous prime is 2013233404393. The next prime is 2013233404417. The reversal of 2013233404403 is 3044043323102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013233404403 - 212 = 2013233400307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013233404003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77432054003 + ... + 77432054028.

It is an arithmetic number, because the mean of its divisors is an integer number (542024378112).

Almost surely, 22013233404403 is an apocalyptic number.

2013233404403 is a deficient number, since it is larger than the sum of its proper divisors (154864108045).

2013233404403 is a wasteful number, since it uses less digits than its factorization.

2013233404403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154864108044.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 2013233404403 its reverse (3044043323102), we get a palindrome (5057276727505).

The spelling of 2013233404403 in words is "two trillion, thirteen billion, two hundred thirty-three million, four hundred four thousand, four hundred three".

Divisors: 1 13 154864108031 2013233404403