Base | Representation |
---|---|
bin | 1011101101111111011… |
… | …0000111001111000001 |
3 | 201020122121121212022121 |
4 | 2323133312013033001 |
5 | 11244302421001233 |
6 | 232253104004241 |
7 | 20354665523611 |
oct | 2733766071701 |
9 | 636577555277 |
10 | 201324000193 |
11 | 78421171138 |
12 | 33027000681 |
13 | 15ca570b244 |
14 | 9a5bc8ca41 |
15 | 538480592d |
hex | 2edfd873c1 |
201324000193 has 2 divisors, whose sum is σ = 201324000194. Its totient is φ = 201324000192.
The previous prime is 201324000181. The next prime is 201324000203. The reversal of 201324000193 is 391000423102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 157170223809 + 44153776384 = 396447^2 + 210128^2 .
It is a cyclic number.
It is not a de Polignac number, because 201324000193 - 229 = 200787129281 is a prime.
It is a super-2 number, since 2×2013240001932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (201324003193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100662000096 + 100662000097.
It is an arithmetic number, because the mean of its divisors is an integer number (100662000097).
Almost surely, 2201324000193 is an apocalyptic number.
It is an amenable number.
201324000193 is a deficient number, since it is larger than the sum of its proper divisors (1).
201324000193 is an equidigital number, since it uses as much as digits as its factorization.
201324000193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 201324000193 its reverse (391000423102), we get a palindrome (592324423295).
The spelling of 201324000193 in words is "two hundred one billion, three hundred twenty-four million, one hundred ninety-three", and thus it is an aban number.
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