Base | Representation |
---|---|
bin | 101101110001101001110010… |
… | …110111001010100110000111 |
3 | 222101211102000022220010022021 |
4 | 231301221302313022212013 |
5 | 202341444002332043042 |
6 | 1552103023255344011 |
7 | 60256123644364531 |
oct | 5561516267124607 |
9 | 871742008803267 |
10 | 201324224096647 |
11 | 5916a13aa99923 |
12 | 1a6b5b97382007 |
13 | 8844a3cc25902 |
14 | 37a02044a0851 |
15 | 1841d899be867 |
hex | b71a72dca987 |
201324224096647 has 2 divisors, whose sum is σ = 201324224096648. Its totient is φ = 201324224096646.
The previous prime is 201324224096573. The next prime is 201324224096683. The reversal of 201324224096647 is 746690422423102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201324224096647 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201324224096594 and 201324224096603.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201324224096687) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100662112048323 + 100662112048324.
It is an arithmetic number, because the mean of its divisors is an integer number (100662112048324).
Almost surely, 2201324224096647 is an apocalyptic number.
201324224096647 is a deficient number, since it is larger than the sum of its proper divisors (1).
201324224096647 is an equidigital number, since it uses as much as digits as its factorization.
201324224096647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6967296, while the sum is 52.
The spelling of 201324224096647 in words is "two hundred one trillion, three hundred twenty-four billion, two hundred twenty-four million, ninety-six thousand, six hundred forty-seven".
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