Base | Representation |
---|---|
bin | 10010110000000001… |
… | …010101111001101011 |
3 | 1220222002210221002222 |
4 | 102300001111321223 |
5 | 312213022323201 |
6 | 13125440144255 |
7 | 1311625525136 |
oct | 226001257153 |
9 | 56862727088 |
10 | 20133011051 |
11 | 85a161820a |
12 | 3a9a60808b |
13 | 1b8b108aba |
14 | d8dc2b21d |
15 | 7cc79191b |
hex | 4b0055e6b |
20133011051 has 2 divisors, whose sum is σ = 20133011052. Its totient is φ = 20133011050.
The previous prime is 20133011029. The next prime is 20133011057. The reversal of 20133011051 is 15011033102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20133011051 - 26 = 20133010987 is a prime.
It is not a weakly prime, because it can be changed into another prime (20133011057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066505525 + 10066505526.
It is an arithmetic number, because the mean of its divisors is an integer number (10066505526).
Almost surely, 220133011051 is an apocalyptic number.
20133011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133011051 is an equidigital number, since it uses as much as digits as its factorization.
20133011051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 20133011051 its reverse (15011033102), we get a palindrome (35144044153).
The spelling of 20133011051 in words is "twenty billion, one hundred thirty-three million, eleven thousand, fifty-one".
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