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201330133313011 is a prime number
BaseRepresentation
bin101101110001101111010011…
…000101000010010111110011
3222101211222021011010102020121
4231301233103011002113303
5202342043103112004021
61552105441510351111
760256423250034553
oct5561572305022763
9871758234112217
10201330133313011
11591716a265360a
121a6b716635b497
138845472256b41
1437a06051db163
1518420d3673741
hexb71bd31425f3

201330133313011 has 2 divisors, whose sum is σ = 201330133313012. Its totient is φ = 201330133313010.

The previous prime is 201330133313009. The next prime is 201330133313119. The reversal of 201330133313011 is 110313331033102.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 201330133313011 - 21 = 201330133313009 is a prime.

It is a super-2 number, since 2×2013301333130112 (a number of 29 digits) contains 22 as substring.

Together with 201330133313009, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (201330133319011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100665066656505 + 100665066656506.

It is an arithmetic number, because the mean of its divisors is an integer number (100665066656506).

Almost surely, 2201330133313011 is an apocalyptic number.

201330133313011 is a deficient number, since it is larger than the sum of its proper divisors (1).

201330133313011 is an equidigital number, since it uses as much as digits as its factorization.

201330133313011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 201330133313011 its reverse (110313331033102), we get a palindrome (311643464346113).

The spelling of 201330133313011 in words is "two hundred one trillion, three hundred thirty billion, one hundred thirty-three million, three hundred thirteen thousand, eleven".