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2013310011253 is a prime number
BaseRepresentation
bin11101010011000010101…
…000001100011101110101
321010110201000222110220211
4131103002220030131311
5230441224330330003
64140522444425421
7265312461506422
oct35230250143565
97113630873824
102013310011253
11706927018292
12286239548271
13117b14c2a888
146d632476d49
153758676996d
hex1d4c2a0c775

2013310011253 has 2 divisors, whose sum is σ = 2013310011254. Its totient is φ = 2013310011252.

The previous prime is 2013310011239. The next prime is 2013310011259. The reversal of 2013310011253 is 3521100133102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1915392336529 + 97917674724 = 1383977^2 + 312918^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013310011253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013310011259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655005626 + 1006655005627.

It is an arithmetic number, because the mean of its divisors is an integer number (1006655005627).

Almost surely, 22013310011253 is an apocalyptic number.

It is an amenable number.

2013310011253 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013310011253 is an equidigital number, since it uses as much as digits as its factorization.

2013310011253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 2013310011253 its reverse (3521100133102), we get a palindrome (5534410144355).

The spelling of 2013310011253 in words is "two trillion, thirteen billion, three hundred ten million, eleven thousand, two hundred fifty-three".