2013310011319 has 2 divisors, whose sum is σ = 2013310011320. Its totient is φ = 2013310011318.

The previous prime is 2013310011287. The next prime is 2013310011331. The reversal of 2013310011319 is 9131100133102.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2013310011319 - 2⁵ = 2013310011287 is a prime.

It is a super-2 number, since 2×2013310011319² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2013310011293 and 2013310011302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013310011359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655005659 + 1006655005660.

It is an arithmetic number, because the mean of its divisors is an integer number (1006655005660).

Almost surely, 2^{2013310011319} is an apocalyptic number.

2013310011319 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013310011319 is an equidigital number, since it uses as much as digits as its factorization.

2013310011319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 2013310011319 in words is "two trillion, thirteen billion, three hundred ten million, eleven thousand, three hundred nineteen".