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20133101412000 = 25325337103257571
BaseRepresentation
bin1001001001111100110100…
…10110111001111010100000
32122021201001110020210201200
410210332122112321322200
510114330042430141000
6110453004043201200
74145366010244503
oct444763226717240
978251043223650
1020133101412000
116462444972985
122311b1ab16200
13b3070a8891a5
144d86395ab13a
1524da95121500
hex124f9a5b9ea0

20133101412000 has 1152 divisors, whose sum is σ = 74514565052928. Its totient is φ = 5143855104000.

The previous prime is 20133101411993. The next prime is 20133101412013. The reversal of 20133101412000 is 21410133102.

20133101412000 is a `hidden beast` number, since 2 + 0 + 13 + 310 + 141 + 200 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 35259371715 + ... + 35259372285.

It is an arithmetic number, because the mean of its divisors is an integer number (64682782164).

Almost surely, 220133101412000 is an apocalyptic number.

20133101412000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20133101412000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (37257282526464).

20133101412000 is an abundant number, since it is smaller than the sum of its proper divisors (54381463640928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20133101412000 is a wasteful number, since it uses less digits than its factorization.

20133101412000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 999 (or 978 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 20133101412000 its reverse (21410133102), we get a palindrome (20154511545102).

The spelling of 20133101412000 in words is "twenty trillion, one hundred thirty-three billion, one hundred one million, four hundred twelve thousand".