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20133120120103 = 25819779779237
BaseRepresentation
bin1001001001111100110110…
…11110010001010100100111
32122021201002202110021102101
410210332123132101110213
510114330112222320403
6110453005552152531
74145366325253204
oct444763336212447
978251082407371
1020133120120103
116462454490621
122311b25238747
13b30711709583
144d863bc7acab
1524da96ab971d
hex124f9b791527

20133120120103 has 4 divisors (see below), whose sum is σ = 20133899925160. Its totient is φ = 20132340315048.

The previous prime is 20133120120101. The next prime is 20133120120119. The reversal of 20133120120103 is 30102102133102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20133120120103 - 21 = 20133120120101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20133120120101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389863800 + ... + 389915437.

It is an arithmetic number, because the mean of its divisors is an integer number (5033474981290).

Almost surely, 220133120120103 is an apocalyptic number.

20133120120103 is a deficient number, since it is larger than the sum of its proper divisors (779805057).

20133120120103 is an equidigital number, since it uses as much as digits as its factorization.

20133120120103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 779805056.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 20133120120103 its reverse (30102102133102), we get a palindrome (50235222253205).

The spelling of 20133120120103 in words is "twenty trillion, one hundred thirty-three billion, one hundred twenty million, one hundred twenty thousand, one hundred three".

Divisors: 1 25819 779779237 20133120120103