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2013321440000 = 2854137113633
BaseRepresentation
bin11101010011000011010…
…011110010101100000000
321010110201211111010012202
4131103003103302230000
5230441240242040000
64140523533412332
7265312660606403
oct35230323625400
97113654433182
102013321440000
11706932513932
1228624133a0a8
13117b173cc850
146d633badd3a
1537587775dd5
hex1d4c34f2b00

2013321440000 has 360 divisors, whose sum is σ = 5484736347552. Its totient is φ = 732856320000.

The previous prime is 2013321439981. The next prime is 2013321440041. The reversal of 2013321440000 is 441233102.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 147673184 + ... + 147686816.

Almost surely, 22013321440000 is an apocalyptic number.

2013321440000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2013321440000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2742368173776).

2013321440000 is an abundant number, since it is smaller than the sum of its proper divisors (3471414907552).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2013321440000 is an equidigital number, since it uses as much as digits as its factorization.

2013321440000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13753 (or 13724 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 2013321440000 its reverse (441233102), we get a palindrome (2013762673102).

The spelling of 2013321440000 in words is "two trillion, thirteen billion, three hundred twenty-one million, four hundred forty thousand".