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2013330301231 is a prime number
BaseRepresentation
bin11101010011000011110…
…101100110000100101111
321010110202110011022112111
4131103003311212010233
5230441300024114411
64140524451344451
7265313126124034
oct35230365460457
97113673138474
102013330301231
11706937516467
122862442b2127
13117b191b2c92
146d63503938b
1537588426721
hex1d4c3d6612f

2013330301231 has 2 divisors, whose sum is σ = 2013330301232. Its totient is φ = 2013330301230.

The previous prime is 2013330301183. The next prime is 2013330301237. The reversal of 2013330301231 is 1321030333102.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013330301231 is a prime.

It is a super-3 number, since 3×20133303012313 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013330301237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006665150615 + 1006665150616.

It is an arithmetic number, because the mean of its divisors is an integer number (1006665150616).

Almost surely, 22013330301231 is an apocalyptic number.

2013330301231 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013330301231 is an equidigital number, since it uses as much as digits as its factorization.

2013330301231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 2013330301231 its reverse (1321030333102), we get a palindrome (3334360634333).

The spelling of 2013330301231 in words is "two trillion, thirteen billion, three hundred thirty million, three hundred one thousand, two hundred thirty-one".