Base | Representation |
---|---|
bin | 1001001001111101001110… |
… | …11001101000110110010111 |
3 | 2122021201121201000000210211 |
4 | 10210332213121220312113 |
5 | 10114331014434413333 |
6 | 110453041501230251 |
7 | 4145404305215623 |
oct | 444764731506627 |
9 | 78251551000724 |
10 | 20133320232343 |
11 | 646254743a93a |
12 | 2311b80262387 |
13 | b30744002996 |
14 | 4d865a68c183 |
15 | 24daa9446ecd |
hex | 124fa7668d97 |
20133320232343 has 2 divisors, whose sum is σ = 20133320232344. Its totient is φ = 20133320232342.
The previous prime is 20133320232251. The next prime is 20133320232409. The reversal of 20133320232343 is 34323202333102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20133320232343 - 221 = 20133318135191 is a prime.
It is a super-3 number, since 3×201333202323433 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20133320232143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066660116171 + 10066660116172.
It is an arithmetic number, because the mean of its divisors is an integer number (10066660116172).
Almost surely, 220133320232343 is an apocalyptic number.
20133320232343 is a deficient number, since it is larger than the sum of its proper divisors (1).
20133320232343 is an equidigital number, since it uses as much as digits as its factorization.
20133320232343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 46656, while the sum is 31.
Adding to 20133320232343 its reverse (34323202333102), we get a palindrome (54456522565445).
The spelling of 20133320232343 in words is "twenty trillion, one hundred thirty-three billion, three hundred twenty million, two hundred thirty-two thousand, three hundred forty-three".
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