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20133321222197 is a prime number
BaseRepresentation
bin1001001001111101001110…
…11101011010100000110101
32122021201121202212022122002
410210332213131122200311
510114331020213102242
6110453041534345045
74145404316510531
oct444764735324065
978251552768562
1020133321222197
116462547a565a7
122311b8065b185
13b3074428b3b1
144d865a868bc1
1524daa9590432
hex124fa775a835

20133321222197 has 2 divisors, whose sum is σ = 20133321222198. Its totient is φ = 20133321222196.

The previous prime is 20133321222121. The next prime is 20133321222263. The reversal of 20133321222197 is 79122212333102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11330433977041 + 8802887245156 = 3366071^2 + 2966966^2 .

It is a cyclic number.

It is not a de Polignac number, because 20133321222197 - 222 = 20133317027893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20133321222197.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20133321222107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066660611098 + 10066660611099.

It is an arithmetic number, because the mean of its divisors is an integer number (10066660611099).

Almost surely, 220133321222197 is an apocalyptic number.

It is an amenable number.

20133321222197 is a deficient number, since it is larger than the sum of its proper divisors (1).

20133321222197 is an equidigital number, since it uses as much as digits as its factorization.

20133321222197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 38.

Adding to 20133321222197 its reverse (79122212333102), we get a palindrome (99255533555299).

The spelling of 20133321222197 in words is "twenty trillion, one hundred thirty-three billion, three hundred twenty-one million, two hundred twenty-two thousand, one hundred ninety-seven".