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2013334323423 = 3671111441141
BaseRepresentation
bin11101010011000100000…
…100111100000011011111
321010110202201201122221120
4131103010010330003133
5230441302041322143
64140525113502023
7265313205245403
oct35230404740337
97113681648846
102013334323423
11706939813395
12286245711913
13117b19c90987
146d6357a5103
153758896d383
hex1d4c413c0df

2013334323423 has 4 divisors (see below), whose sum is σ = 2684445764568. Its totient is φ = 1342222882280.

The previous prime is 2013334323409. The next prime is 2013334323461. The reversal of 2013334323423 is 3243234333102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2013334323423 - 28 = 2013334323167 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013334303423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335555720568 + ... + 335555720573.

It is an arithmetic number, because the mean of its divisors is an integer number (671111441142).

Almost surely, 22013334323423 is an apocalyptic number.

2013334323423 is a deficient number, since it is larger than the sum of its proper divisors (671111441145).

2013334323423 is an equidigital number, since it uses as much as digits as its factorization.

2013334323423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 671111441144.

The product of its (nonzero) digits is 93312, while the sum is 33.

Adding to 2013334323423 its reverse (3243234333102), we get a palindrome (5256568656525).

The spelling of 2013334323423 in words is "two trillion, thirteen billion, three hundred thirty-four million, three hundred twenty-three thousand, four hundred twenty-three".

Divisors: 1 3 671111441141 2013334323423