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2013341203 = 4149105883
BaseRepresentation
bin111100000000001…
…0010011000010011
312012022110022220201
41320000102120103
513110403404303
6531440520031
7100615055266
oct17000223023
95168408821
102013341203
1194352a055
12482320017
13261168973
1415156ccdd
15bbb4a81d
hex78012613

2013341203 has 4 divisors (see below), whose sum is σ = 2062447128. Its totient is φ = 1964235280.

The previous prime is 2013341189. The next prime is 2013341237. The reversal of 2013341203 is 3021433102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2013341203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2013341243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24552901 + ... + 24552982.

It is an arithmetic number, because the mean of its divisors is an integer number (515611782).

Almost surely, 22013341203 is an apocalyptic number.

2013341203 is a deficient number, since it is larger than the sum of its proper divisors (49105925).

2013341203 is an equidigital number, since it uses as much as digits as its factorization.

2013341203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49105924.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 2013341203 is about 44870.2708148725. The cubic root of 2013341203 is about 1262.7163207801.

Adding to 2013341203 its reverse (3021433102), we get a palindrome (5034774305).

The spelling of 2013341203 in words is "two billion, thirteen million, three hundred forty-one thousand, two hundred three".

Divisors: 1 41 49105883 2013341203