Base | Representation |
---|---|
bin | 11101010011000100101… |
… | …101110101101110110111 |
3 | 21010110210110220101202222 |
4 | 131103010231311232313 |
5 | 230441312312423211 |
6 | 4140530135352555 |
7 | 265313365343036 |
oct | 35230455655667 |
9 | 7113713811688 |
10 | 2013345045431 |
11 | 706944876a55 |
12 | 28624922275b |
13 | 117b1c276065 |
14 | 6d636d9671d |
15 | 3758988a1db |
hex | 1d4c4b75bb7 |
2013345045431 has 2 divisors, whose sum is σ = 2013345045432. Its totient is φ = 2013345045430.
The previous prime is 2013345045419. The next prime is 2013345045493. The reversal of 2013345045431 is 1345405433102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2013345045431 - 218 = 2013344783287 is a prime.
It is a super-2 number, since 2×20133450454312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2013345045391 and 2013345045400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2013345035431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006672522715 + 1006672522716.
It is an arithmetic number, because the mean of its divisors is an integer number (1006672522716).
Almost surely, 22013345045431 is an apocalyptic number.
2013345045431 is a deficient number, since it is larger than the sum of its proper divisors (1).
2013345045431 is an equidigital number, since it uses as much as digits as its factorization.
2013345045431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 2013345045431 in words is "two trillion, thirteen billion, three hundred forty-five million, forty-five thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •