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2013353004601 is a prime number
BaseRepresentation
bin11101010011000101001…
…100001100111000111001
321010110211000212202201001
4131103011030030320321
5230441321332121401
64140531022125001
7265313523112441
oct35230514147071
97113730782631
102013353004601
11706949312884
1228624ba20761
13117b20b01a23
146d638069121
153758a40d601
hex1d4c530ce39

2013353004601 has 2 divisors, whose sum is σ = 2013353004602. Its totient is φ = 2013353004600.

The previous prime is 2013353004583. The next prime is 2013353004613. The reversal of 2013353004601 is 1064003533102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1684152467001 + 329200537600 = 1297749^2 + 573760^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013353004601 - 223 = 2013344615993 is a prime.

It is a super-2 number, since 2×20133530046012 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2013353004601.

It is not a weakly prime, because it can be changed into another prime (2013353004661) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006676502300 + 1006676502301.

It is an arithmetic number, because the mean of its divisors is an integer number (1006676502301).

Almost surely, 22013353004601 is an apocalyptic number.

It is an amenable number.

2013353004601 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013353004601 is an equidigital number, since it uses as much as digits as its factorization.

2013353004601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 2013353004601 its reverse (1064003533102), we get a palindrome (3077356537703).

The spelling of 2013353004601 in words is "two trillion, thirteen billion, three hundred fifty-three million, four thousand, six hundred one".