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201336751453 is a prime number
BaseRepresentation
bin1011101110000010011…
…0110000010101011101
3201020200111121200202111
42323200212300111131
511244314202021303
6232254241154021
720355212102365
oct2734046602535
9636614550674
10201336751453
1178428390372
123302b32b911
1315ca8254176
149a5d84b9a5
1553859c3b6d
hex2ee09b055d

201336751453 has 2 divisors, whose sum is σ = 201336751454. Its totient is φ = 201336751452.

The previous prime is 201336751433. The next prime is 201336751471. The reversal of 201336751453 is 354157633102.

201336751453 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 195843421764 + 5493329689 = 442542^2 + 74117^2 .

It is a cyclic number.

It is not a de Polignac number, because 201336751453 - 213 = 201336743261 is a prime.

It is a super-2 number, since 2×2013367514532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201336751433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100668375726 + 100668375727.

It is an arithmetic number, because the mean of its divisors is an integer number (100668375727).

Almost surely, 2201336751453 is an apocalyptic number.

It is an amenable number.

201336751453 is a deficient number, since it is larger than the sum of its proper divisors (1).

201336751453 is an equidigital number, since it uses as much as digits as its factorization.

201336751453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 40.

The spelling of 201336751453 in words is "two hundred one billion, three hundred thirty-six million, seven hundred fifty-one thousand, four hundred fifty-three".