Base | Representation |
---|---|
bin | 10010110000000101… |
… | …001100001111001001 |
3 | 1220222011201012011222 |
4 | 102300011030033021 |
5 | 312213302120131 |
6 | 13125513531425 |
7 | 1311640226612 |
oct | 226005141711 |
9 | 56864635158 |
10 | 20134020041 |
11 | 85a2147293 |
12 | 3a9aa13b75 |
13 | 1b8b3a0135 |
14 | d90010c09 |
15 | 7cc8e087b |
hex | 4b014c3c9 |
20134020041 has 2 divisors, whose sum is σ = 20134020042. Its totient is φ = 20134020040.
The previous prime is 20134020017. The next prime is 20134020079. The reversal of 20134020041 is 14002043102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10403184016 + 9730836025 = 101996^2 + 98645^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20134020041 is a prime.
It is a super-2 number, since 2×201340200412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20134080041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10067010020 + 10067010021.
It is an arithmetic number, because the mean of its divisors is an integer number (10067010021).
Almost surely, 220134020041 is an apocalyptic number.
It is an amenable number.
20134020041 is a deficient number, since it is larger than the sum of its proper divisors (1).
20134020041 is an equidigital number, since it uses as much as digits as its factorization.
20134020041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 20134020041 its reverse (14002043102), we get a palindrome (34136063143).
The spelling of 20134020041 in words is "twenty billion, one hundred thirty-four million, twenty thousand, forty-one".
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