Base | Representation |
---|---|
bin | 1011101110000011001… |
… | …1111101101100000101 |
3 | 201020200202010121111202 |
4 | 2323200303331230011 |
5 | 11244321043322041 |
6 | 232254443312245 |
7 | 20355253403342 |
oct | 2734063755405 |
9 | 636622117452 |
10 | 201340214021 |
11 | 7842a3358a1 |
12 | 3303051b685 |
13 | 15ca8b9721b |
14 | 9a600ad7c9 |
15 | 5385e59a9b |
hex | 2ee0cfdb05 |
201340214021 has 2 divisors, whose sum is σ = 201340214022. Its totient is φ = 201340214020.
The previous prime is 201340213969. The next prime is 201340214057. The reversal of 201340214021 is 120412043102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123351273796 + 77988940225 = 351214^2 + 279265^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201340214021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201340213984 and 201340214002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201340214071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670107010 + 100670107011.
It is an arithmetic number, because the mean of its divisors is an integer number (100670107011).
Almost surely, 2201340214021 is an apocalyptic number.
It is an amenable number.
201340214021 is a deficient number, since it is larger than the sum of its proper divisors (1).
201340214021 is an equidigital number, since it uses as much as digits as its factorization.
201340214021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 201340214021 its reverse (120412043102), we get a palindrome (321752257123).
The spelling of 201340214021 in words is "two hundred one billion, three hundred forty million, two hundred fourteen thousand, twenty-one".
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