Base | Representation |
---|---|
bin | 1011101110000011010… |
… | …0000001111100010001 |
3 | 201020200202011111101221 |
4 | 2323200310001330101 |
5 | 11244321044401231 |
6 | 232254443525041 |
7 | 20355253505206 |
oct | 2734064017421 |
9 | 636622144357 |
10 | 201340231441 |
11 | 7842a347998 |
12 | 33030529781 |
13 | 15ca8ba212b |
14 | 9a600b5cad |
15 | 5385e5ed11 |
hex | 2ee0d01f11 |
201340231441 has 2 divisors, whose sum is σ = 201340231442. Its totient is φ = 201340231440.
The previous prime is 201340231387. The next prime is 201340231457. The reversal of 201340231441 is 144132043102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 127031652225 + 74308579216 = 356415^2 + 272596^2 .
It is a cyclic number.
It is not a de Polignac number, because 201340231441 - 225 = 201306677009 is a prime.
It is not a weakly prime, because it can be changed into another prime (201340231241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100670115720 + 100670115721.
It is an arithmetic number, because the mean of its divisors is an integer number (100670115721).
Almost surely, 2201340231441 is an apocalyptic number.
It is an amenable number.
201340231441 is a deficient number, since it is larger than the sum of its proper divisors (1).
201340231441 is an equidigital number, since it uses as much as digits as its factorization.
201340231441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 201340231441 its reverse (144132043102), we get a palindrome (345472274543).
The spelling of 201340231441 in words is "two hundred one billion, three hundred forty million, two hundred thirty-one thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •