Base | Representation |
---|---|
bin | 101101110001111000101101… |
… | …101111000101100011011011 |
3 | 222101212221100210120201022210 |
4 | 231301320231233011203123 |
5 | 202342224310010020443 |
6 | 1552114233054250203 |
7 | 60260231642240061 |
oct | 5561705557054333 |
9 | 871787323521283 |
10 | 201340244220123 |
11 | 59175a10a29798 |
12 | 1a6b91084b6963 |
13 | 88463c3c06508 |
14 | 37a0cc3d90031 |
15 | 18424c613cc33 |
hex | b71e2dbc58db |
201340244220123 has 4 divisors (see below), whose sum is σ = 268453658960168. Its totient is φ = 134226829480080.
The previous prime is 201340244220121. The next prime is 201340244220127. The reversal of 201340244220123 is 321022442043102.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 201340244220123 - 21 = 201340244220121 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (201340244220121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33556707370018 + ... + 33556707370023.
It is an arithmetic number, because the mean of its divisors is an integer number (67113414740042).
Almost surely, 2201340244220123 is an apocalyptic number.
201340244220123 is a deficient number, since it is larger than the sum of its proper divisors (67113414740045).
201340244220123 is an equidigital number, since it uses as much as digits as its factorization.
201340244220123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67113414740044.
The product of its (nonzero) digits is 18432, while the sum is 30.
Adding to 201340244220123 its reverse (321022442043102), we get a palindrome (522362686263225).
The spelling of 201340244220123 in words is "two hundred one trillion, three hundred forty billion, two hundred forty-four million, two hundred twenty thousand, one hundred twenty-three".
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